Vulnerability Database · PyPI · ipython · Version

ipython 8.4.0

8.4.0 is affected by 3 vulnerabilities.

The vulnerabilities that cover this exact version are listed below with the fixed version to move to. The upgrade Vulert recommends: 9.17.1.

Critical 0 High 0 Medium 0 Low 1 Unrated 2

Released 28 May 2022 Licence non-standard Also known from other sources 2 Newer releases 199 Database updated 23/Oct/2026

Release and licence data published by PyPI. Licence information is not legal advice.

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01 Vulnerabilities affecting this version

ipython 8.4.0 vulnerabilities

3 vulnerabilities cover ipython 8.4.0. Open the full list in the database.

Vulnerability Severity Fixed version Disclosed
CVE-2023-24816: IPython Command Injection Vulnerability 4.5 low 8.10.0 10 Feb 2023
CVE-2023-24816: IPython Command Injection Vulnerability N/A unrated 385d69325319a5972ee9b5983638e3617f21cb1f 10 Feb 2023
CVE-2022-21699: Arbitrary Code Execution in IPython N/A unrated 46a51ed69cdf41b4333943d9ceeb945c4ede5668 19 Jan 2022

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Questions

About ipython 8.4.0

Is ipython 8.4.0 vulnerable?

Yes. 3 vulnerabilities in the Vulert database cover ipython 8.4.0: 0 critical, 0 high, 0 medium and 1 low, plus 2 not yet rated. The upgrade Vulert recommends is 9.17.1, and each entry above names the fixed version to move to.

Which version of ipython should I use instead of 8.4.0?

9.17.1 is the version Vulert recommends for this release line. The version table on the package page lists every release with the vulnerabilities recorded against it.

Is 8.4.0 the latest release of ipython?

No. 8.4.0 was published 28 May 2022, and newer releases exist. Newer is not automatically safer — the version table on the package page shows what each release carries.

How do I monitor ipython for upcoming vulnerabilities?

Upload the manifest or SBOM for your application at vulert.com/scanner and Vulert keeps checking the ipython version you actually run against new disclosures, then alerts you when one affects it. There is no installation and no source-code access required.