Vulnerability Database · PyPI · scikit-learn · Version

scikit-learn 1.2.2

1.2.2 is affected by 3 vulnerabilities.

The vulnerabilities that cover this exact version are listed below with the fixed version to move to. The upgrade Vulert recommends: 1.9.1.

Critical 1 High 0 Medium 2 Low 0 Unrated 0

Released 09 Mar 2023 Licence non-standard Also known from other sources 2 Newer releases 76 Database updated 23/Oct/2026

Release and licence data published by PyPI. Licence information is not legal advice.

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01 Vulnerabilities affecting this version

scikit-learn 1.2.2 vulnerabilities

3 vulnerabilities cover scikit-learn 1.2.2. Open the full list in the database.

Vulnerability Severity Fixed version Disclosed
CVE-2020-13092: scikit-learn Deserialization of Untrusted Data 9.8 critical No fix published 24 May 2022
CVE-2024-5206: scikit-learn sensitive data leakage vulnerability 5.3 medium 1.5.0 06 Jun 2024
Sensitive Data Leakage in scikit-learn's TfidfVectorizer 4.7 medium 70ca21f106b603b611da73012c9ade7cd8e438b8 06 Jun 2024

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Questions

About scikit-learn 1.2.2

Is scikit-learn 1.2.2 vulnerable?

Yes. 3 vulnerabilities in the Vulert database cover scikit-learn 1.2.2: 1 critical, 0 high, 2 medium and 0 low. The upgrade Vulert recommends is 1.9.1, and each entry above names the fixed version to move to.

Which version of scikit-learn should I use instead of 1.2.2?

1.9.1 is the version Vulert recommends for this release line. The version table on the package page lists every release with the vulnerabilities recorded against it.

Is 1.2.2 the latest release of scikit-learn?

No. 1.2.2 was published 09 Mar 2023, and newer releases exist. Newer is not automatically safer — the version table on the package page shows what each release carries.

How do I monitor scikit-learn for upcoming vulnerabilities?

Upload the manifest or SBOM for your application at vulert.com/scanner and Vulert keeps checking the scikit-learn version you actually run against new disclosures, then alerts you when one affects it. There is no installation and no source-code access required.